Find the midpoint of ACA(0,0) B (0,a) C(a,a) D(a,0)

Answer :

Answer:

[tex]\begin{equation*} (\frac{a}{2},\frac{a}{2}) \end{equation*}[/tex]

Explanation:

Given the coordinates as A(0,0), B (0,a), C(a,a), and D(a,0), let's go ahead and draw a sketch as seen below;

Recall the below midpoint formula;

[tex]Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})[/tex]

Solving for the midpoints of AC, we'll have;

[tex]\begin{gathered} Midpoint=(\frac{0+a}{2},\frac{0+a}{2}) \\ \\ =(\frac{a}{2},\frac{a}{2}) \end{gathered}[/tex]

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