Given:
The time taken to cover the distance is t=5.00 h.
The average velocity of cyclist is v=12.0 km/h.
The displacement of the cyclist can be expressed as,
[tex]d=vt[/tex]
Substitute the known values,
[tex]\begin{gathered} d=(12.0\text{ km/h)(5.00 h)} \\ =60.0\text{ km} \end{gathered}[/tex]
Thus, the displacement of cyclist is 60.0 km. Since the cyclist move in the southwest direction therefore, the displacement is in the southwest direction.
