A game is played by drawing 4 cards from an ordinary deck and replacing each card after it is drawn. Find the probability that at least 1 ace is drawn.

Answer :

Answer:

[tex]0.066[/tex]

Explanation:

Here, we want to get the probability that at least 1 ace is drawn

There are 4 aces in a deck of cards

The total number of cards is 52

This means we have a total of 48 non-ace cards

The probability of picking at least an ace means that:

1 ace, 3 others

or 2 aces, 2 others

or

3 ace, 1 other

or

4 ace, no other

These are all the possible pickling combinations

The probability of picking an ace is the number of ace cards divided by the total number of cards which are 4/52 = 1/13

For non-ace cards, we have the probability as 48/52 = 12/13

We are going to add the combinations

We have that as follows:

[tex]\begin{gathered} (\frac{1}{13}\times\frac{12}{13}\times\frac{12}{13}\times\frac{12}{13})\text{ + (}\frac{1}{13}\times\frac{1}{13}\times\frac{12}{13}\times\frac{12}{13})\text{ + (}\frac{1}{13}\times\frac{1}{13}\times\frac{1}{13}\times\frac{12}{13}) \\ +\text{ (}\frac{1}{13}\times\frac{1}{13}\times\frac{1}{13}\times\frac{1}{13}) \end{gathered}[/tex]

Finally, we simply the above so as to get a single fraction

We have that as follows:

[tex]\frac{1728}{28561}+\frac{144}{28561}_{}+\frac{12}{28561}+\frac{1}{28561}=\text{ }\frac{1885}{28,561}\text{ = 0.066}[/tex]