The given equation is
[tex]-12x+8y=-48[/tex]The equation has 2 variables (x and y)
To solve it, we have to assume a value of x and get its corresponding value of y
Let x = 1, then substitute it in the equation and solve it to find y
[tex]\begin{gathered} x=1 \\ -12(1)+8y=-48 \\ -12+8y=-48 \end{gathered}[/tex]Add 12 to both sides
[tex]\begin{gathered} -12+12+8y=-48+12 \\ 0+8y=-36 \\ 8y=-36 \end{gathered}[/tex]Divide both sides by 8
[tex]\begin{gathered} \frac{8y}{8}=\frac{-36}{8} \\ y=-4.5 \end{gathered}[/tex]At x = 1, y = -4.5
Then one solution of the equation is (1, -4.5)