Answer:
[tex]\begin{gathered} (h\circ k)(3)=3 \\ (k\circ h)(-4b)=-4b \end{gathered}[/tex]
Explanation:
We need to use the definition for a composition of functions and inverse functions.
If h and k are inverse functions:
[tex](k\circ h)(x)=(h\circ k)(x)=x[/tex]
Then, the composition of two inverse functions give us the input (x, in the definition above).
Thus:
[tex]\begin{gathered} (h\circ k)(3)=3 \\ (k\circ h)(-4b)=-4b \end{gathered}[/tex]
