We have the expression:
[tex]\frac{h^2+3h-10}{h^2-12h+20}[/tex]
To determine the restrictions we factor the quadratic function in the denominator (Since is the only one that is capable of making the expression not make sense):
*What we will be looking are the values that make that function zero:
[tex]h^2-12h+20=(h-10)(h-2)[/tex]
From this, we can see that the values that present a restriction (The values that will make the denominator zero) are:
h = 10 & h = 2.
So, the two answers are h = 10 & h = 2.
