Find the exact value of tan0 if csc0=-4/3and and the terminal side of 0 lies in Quadrant III.

Find The Exact Value Of Tan0 If Csc043and And The Terminal Side Of 0 Lies In Quadrant III class=

Answer :

Answer:

D. tan(θ) = 3√7/7

Explanation:

csc(θ) is equal to the hypotenuse over the opposite side, so if csc(θ) = -4/3, we can represent the angle with the following triangle

So, we can calculate the missing side using the Pythagorean theorem as follows

[tex]\begin{gathered} x=\sqrt[]{4^2-3^2} \\ x=\sqrt[]{16-9} \\ x=\sqrt[]{7} \end{gathered}[/tex]

Now, the tangent of the angle is calculated as:

[tex]\begin{gathered} \tan (\theta)=\frac{Opposite\text{ side}}{Adjacent\text{ side}} \\ \tan (\theta)=\frac{3}{\sqrt[]{7}} \end{gathered}[/tex]

Then, the tangent is equal to:

[tex]\tan (\theta)=\frac{3}{\sqrt[]{7}}\cdot\frac{\sqrt[]{7}}{\sqrt[]{7}}=\frac{3\sqrt[]{7}}{7}[/tex]

Therefore, the answer is

D. tan(θ) = 3√7/7

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