Answer :
We will have the following:
First, we solve both expressions for "y", that is:
[tex]\begin{gathered} 3x-7y=-4\Rightarrow-7y=-3x-4 \\ \Rightarrow y=\frac{3}{7}x+\frac{4}{7} \\ \\ and \\ \\ 2x-5y=-3\Rightarrow-5y=-2x-3 \\ \Rightarrow y=\frac{2}{5}x+\frac{3}{5} \end{gathered}[/tex]Now, we equal both expressions:
[tex]\begin{gathered} \frac{3}{7}x+\frac{4}{7}=\frac{2}{5}x+\frac{3}{5}\Rightarrow\frac{1}{35}x=\frac{1}{35} \\ \\ \Rightarrow x=1 \end{gathered}[/tex]Now, we determine the value of y:
[tex]y=\frac{2}{5}(1)+\frac{3}{5}\Rightarrow y=1[/tex]So, the solution is:
[tex](1,1)[/tex]