What is the probability of rolling a die one time and having it land on a number greater than 4?

Let:
n = Number of outcomes = 6
A = roll a number greater than 4 = 2
Therefore:
[tex]\begin{gathered} P(A)=\frac{A}{n} \\ P(A)=\frac{2}{6}=\frac{1}{3}=0.33 \end{gathered}[/tex]Answer:
33%