Answered

A punter kicks a football. Its height (h) in meters, t seconds after the kick is givenby the equation: h(t) = -4.912t^2 +18.24t +0.8. The height of an approaching blocker'shands is modeled by the equation: g(t) = -1.43t+4.26, using the same time. Can theblocker knock down the punt? If so, at what time does this happen?

Answer :

[tex]t=\frac{-b\pm\sqrt[]{b^2-4ac}\text{ }}{2a}[/tex][tex]t=\frac{19.67\text{ \pm}\sqrt[]{(19.67)^2-4\cdot4.9\cdot3.46}}{2\cdot4.9}[/tex][tex]t=\frac{19.67\pm17.86}{9.8}[/tex][tex]-[/tex][tex]t_1=3.82[/tex][tex]t_2=\text{ 0.1}8[/tex]

View image YAPHETP735637

Go Question: Other Questions