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[tex] \frac{1}{2} {x}^{2} + 1 = 2 \times - 1[/tex]Solve the equation

Answer :

Solve the system of equations:

4x-2y=10 (1)

y=2x-5 (2)

We can substitute 2 in 1:

4x-2(2x-5)=10

4x-4x+10=10

0=0

Since the solution of the system of equation is 0=0 we can say that it has infinite solutions.

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