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I need help with this practice problem It’s from my trig bookI attempted this problem earlier, later, if you can, check if I am correct. I will send a pic of my work.

I Need Help With This Practice Problem Its From My Trig BookI Attempted This Problem Earlier Later If You Can Check If I Am Correct I Will Send A Pic Of My Work class=

Answer :

Given the right triangle:

Taking the cosine of the angle θ:

[tex]\cos \theta=\frac{2\sqrt[]{6}}{2\sqrt[]{15}}=\frac{\sqrt[]{2}}{\sqrt[]{5}}[/tex]

Now, taking the arc cosine to find θ:

[tex]\begin{gathered} \theta=\arccos (\sqrt[]{\frac{2}{5}}) \\ \therefore\theta\approx50.8\degree^{} \end{gathered}[/tex]

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