Answered

Find the equation of a line passing through the point (0,1) and parallel to the line 2x – 3y = 6.

Answer :

The given equation of the line is

[tex]\begin{gathered} 2x-3y=6 \\ 3y=2x-6 \\ y=\frac{2}{3}x-2 \end{gathered}[/tex]

Hence slope of the line is

[tex]\frac{2}{3}[/tex]

Since the line passing through (0,1) parallel to the given line then slope is same for both of them

Since (0,1) is a point so the intercept is c=1

So the equation is

[tex]\begin{gathered} y=mx+c \\ y=\frac{2}{3}x+1 \end{gathered}[/tex]

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