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calculate the surface area of a tetrahedron with four faces and a base of 1 square foot and a height of 0.866 foot

Calculate The Surface Area Of A Tetrahedron With Four Faces And A Base Of 1 Square Foot And A Height Of 0866 Foot class=

Answer :

The surface area is given by:

[tex]SA=B+\frac{1}{2}ph[/tex]

Where:

B = Area of the base

h = height

p = Perimeter of the base

so:

[tex]\begin{gathered} SA=1+\frac{1}{2}(4)(0.866) \\ SA=2.732ft^2 \end{gathered}[/tex]

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