Answer :
we have the expression
[tex]\sqrt[]{72}[/tex]Remember that
[tex]72=2^3\cdot3^2[/tex]substitute
[tex]\sqrt[]{2^3\cdot3^2}=2\cdot3\sqrt[]{2}=6\sqrt[]{2}[/tex]therefore
a=6
b=2
we have the expression
[tex]\sqrt[]{72}[/tex]Remember that
[tex]72=2^3\cdot3^2[/tex]substitute
[tex]\sqrt[]{2^3\cdot3^2}=2\cdot3\sqrt[]{2}=6\sqrt[]{2}[/tex]therefore
a=6
b=2