Answered

Given the equation of the circle, identify the center and radius (x + 1) ^ 2 + (y - 1) ^ 2 = 36

Answer :

The form of the equation of the circle is

[tex](x-h)^2+(y-k)^2=r^2[/tex]

(h, k) is the center

r is the radius

Let us compare it with the given equation to find the center and the radius

[tex](x+1)^2+(y-1)^2=36[/tex]

From the comparing

h = -1

k = 1

r^2 = 36

Find the square root of 36 to get r

[tex]\begin{gathered} r=\sqrt[]{36} \\ r=6 \end{gathered}[/tex]

The center is (-1, 1) and the radius is 6

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