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Zeros 4 and -3iI already asked for the last question, but I’m confused for the i

Zeros 4 And 3iI Already Asked For The Last Question But Im Confused For The I class=

Answer :

Given:

The zeros of the polynomial are 4 and 3i.

Required:

To find the polynomial of the function.

Explanation:

Here

[tex]\begin{gathered} x=4 \\ x=-3i \end{gathered}[/tex][tex]\begin{gathered} x-4=0\text{ and} \\ x+3i=0 \end{gathered}[/tex]

Therefore

[tex]\begin{gathered} (x-4)(x+3i)=0 \\ \\ x^2-4x-3ix-12i=0 \\ \\ x^2-(4+3i)x-12i=0 \end{gathered}[/tex]

Final Answer:

[tex]x^2-(4+3i)x-12i=0[/tex]

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