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Consider the function y=(x−5)2+2.(a) Give the coordinates of the vertex of the graph of the function.(b) Graph the function on a window that includes the vertex.

Consider The Function Yx522a Give The Coordinates Of The Vertex Of The Graph Of The Functionb Graph The Function On A Window That Includes The Vertex class=

Answer :

Given

[tex]y=(x-5)^2+2[/tex]

Procedure

(a) The vertex of a parabola is the point where the parabola crosses its axis of symmetry.

The vertex is at (5, 2)

(b)

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