Find the area and perimeter of the following trapezoid. round to the nearest whole number

Find The Area And Perimeter Of The Following Trapezoid Round To The Nearest Whole Number class=

Answer :

First, I will re-sketch the image

First, we need to find x

Using the trig. ratio

[tex]\tan \theta=\frac{opposite}{adjacent}[/tex][tex]\tan 45=\frac{6}{x}[/tex]

cross-multiply

[tex]x\tan 45=6[/tex][tex]x\times1=6[/tex][tex]x=6[/tex]

Next, we need to find y

Using the trig. ratio

[tex]\sin \theta=\frac{opposite}{hypotenuse}[/tex][tex]\sin 45=\frac{6}{y}[/tex]

cross-multiply

[tex]y\sin 45=6[/tex]

Divide both-side of the equation by sin45

[tex]y=\frac{6}{\sin 45}[/tex][tex]y=8.485[/tex]

Area of a trapezoid is given by the formula;

[tex]A=\frac{1}{2}(a+b)h[/tex]

From the sketch above,

a=12

b=24

h=6

substitute the value and then evaluate

[tex]A=\frac{1}{2}(12+24)6[/tex][tex]=108\text{ square unit}[/tex]

Perimeter is the distance around the shape

[tex]\text{Perimeter}=8.485+12+8.485+24[/tex][tex]\text{perimeter }\approx\text{ 53}[/tex]

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