Answer :
We have:
each CD = x
so
[tex]221+11x=256[/tex]and solve for :
[tex]\begin{gathered} 221+11x-221=256-221 \\ 11x=35 \\ \frac{11x}{11}=\frac{35}{11} \\ x=3\frac{2}{11}=3.18 \end{gathered}[/tex]answer: 3 CDs
We have:
each CD = x
so
[tex]221+11x=256[/tex]and solve for :
[tex]\begin{gathered} 221+11x-221=256-221 \\ 11x=35 \\ \frac{11x}{11}=\frac{35}{11} \\ x=3\frac{2}{11}=3.18 \end{gathered}[/tex]answer: 3 CDs