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A circle is centered at (5,-3) and has a radius of 16.Complete the equation of the circle.=;.: 4:: 16:: (y - 3):: 256:: (x – 5):: (x + 5)2:: (y + 3)2

A Circle Is Centered At 53 And Has A Radius Of 16Complete The Equation Of The Circle 4 16 Y 3 256 X 5 X 52 Y 32 class=

Answer :

The equation of the circle centered at (h,k) with radius r is:

[tex](x-h)^2+(y-k)^2=r^2[/tex]

In this case, the center is (5, -3) and the radius is 16, then the equation is:

[tex]\begin{gathered} (x-5)^2+(y-(-3))^2=16^2 \\ (x-5)^2+(y+3)^2=256 \end{gathered}[/tex]

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