Answer :
The equation is given as
[tex]x^2-8x+13=0[/tex]Solve the quadratic expression by quadratic formula
[tex]x=\frac{8\pm\sqrt[]{64-52}}{2}=\frac{8\pm\sqrt[]{12}}{2}=\frac{8\pm2\sqrt[]{3}}{2}=4\pm\sqrt[]{3}[/tex]Hence the value of x is obtained as
[tex]4+\sqrt[]{3},4-\sqrt[]{3}[/tex]