Answered

If CD = 2x, DE = x − 1, and CE = 17, what is DE?

If CD 2x DE X 1 And CE 17 What Is DE class=

Answer :

Answer:

DE = 5

Explanation:

From the information given,

CD = 2x

DE = x - 1

CE = 17

CD + DE = CE

Thus,

2x + x - 1 = 17

3x - 1 = 17

3x = 17 + 1 = 18

x = 18/3

x = 6

DE = x - 1 = 6 - 1

DE = 5

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