Answer:
[tex]\sf y =\dfrac{1}{4}x-1[/tex]
Step-by-step explanation:
y = -4x + 3
Slope of the above line m₁ = -4
[tex]\sf \text{ Slope of the perpendicular line = m = $\dfrac{-1}{m_1}$}[/tex]
[tex]\sf m =\dfrac{-1}{-4}=\dfrac{1}{4}[/tex]
Equation of the line in slope y-intercept form: y =mx + b
m is the slope and b is the y-intercept.
[tex]\sf y = \dfrac{1}{4}x + b[/tex]
Line contains the point (8 , 1). Substitute in the above equation.
[tex]\sf 1 = \dfrac{1}{4}*8 + b\\\\1 = 2 +b\\\\1-2 = b\\\\ b = -1[/tex]
[tex]\sf y = \dfrac{1}{4}x - 1[/tex]
