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draw the structure of the major product formed in the given reaction when the aromatic aldehyde is present in excess. an aldehyde and ester react with methoxide in methanol. the aldehyde consists of two fused benzene rings. if the top fused carbon is arbitrarily numbered 1 and the ring numbered clockwise, there is an aldehyde substituent on carbon 3 and a methoxy substituent on carbon 8. the ester is a carbonyl bonded to methyl and methoxy.

Answer :

TUTORCONSORTIUM344GO

When combined with methyl acetate, the chemical 6-methoxy-2 naphthaldehyde undergoes an aldol addition reaction to produce methyl 3-hydroxy-3-(6-methoxynaphthalen-2-yl)propanoate. The aldol addition product undergoes dehydration to create the aldol condensed product, (E)-methyl 3-(6-methoxynaphthalen-2-yl)acrylate.

What is aldol condensation reaction?

In an aldol condensation, an enolate ion combines with a carbonyl molecule in the presence of an acid/base catalyst to produce either a hydroxylated aldehyde or ketone, which is then dehydrated to produce a conjugated enone. It is an effective process for creating carbon-carbon bonds.

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