Answer:
Step-by-step explanation:
If x
1
=2 ,y
1
=
16
3
dx
dy
=(2.2
−2x
−2
−x
)ln2
(
dx
dy
)
x=2
=
8
1
−
4
1
=−
8
1
ln2=m
(x−x
1
)m=y−y
1
(x−2)(−
8
1
ln2)=y−
16
3
(2ln2)x+16y−3−4ln2=0 is the tangent at the point with abscissa
′
2
′
