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(Forces and the Laws of Motion pg. 141; Friction) (Problem 4)
A box of books weighing 325 N moves at a constant velocity across the
floor when the box is pushed with a force of 425 N exerted downward at an
angle of 35.2° below the horizontal. Find μk between the box and the floor.

Answer :

ONYEBUCHINNAJIGO

The coefficient of kinetic friction is determined as 0.75.

What is coefficient of friction?

The coefficient of kinetic friction is calculated by applying the newton's second law of motion.

Fsinθ - Ff = ma

where;

  • Ff is frictional force
  • θ is angle of applied force

W = mg

where;

  • m is mass of the box

m = W/g

m = 325/9.8

m = 33.2 kg

425 sin(35.2)   -  Ff = 33.2a

425 sin(35.2)   -  μW = 33.2a

at constant velocity, a = 0

425 sin(35.2)   -  μW= 0

μW = 244.98

μ = 244.98/W

μ = 244.98/325

μ = 0.75

Thus, the coefficient of kinetic friction is 0.75.

Learn more about coefficient of friction here: https://brainly.com/question/20241845

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