Answer:
Step-by-step explanation:
d)
[tex]\displaystyle\\\frac{h}{2h+5} +\frac{5}{6} =\\\\\frac{h*6+5*(2h+5)}{(2h+5)*6} =\\\\\frac{6h+2h(5)+5(5)}{2h(6)+5(6)} \\\\\frac{6h+10y+25}{12h+30} =\\\\\frac{16h+25}{12h+30}[/tex]
g)
[tex]\displaystyle\\\frac{3n}{(2n-1)^2} -\frac{5}{2n-1} =\\\\\frac{3n*1 -5*(2n-1)^}{(2n-1)^2}=\\\\\frac{3n(1)-2n(5)-1(-5)}{(2n-1)^2}=\\\\\frac{3n-10n+5}{(2n-1)^2} =\\\\\frac{-7n+5}{(2n-1)^2}[/tex]
