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Two planes, which are 2940 miles apart, fly toward each other. Their speeds differ by 35mph. If they pass each other in 4 hours, what is the speed of each?

Answer :

SQDANCEFANGO

Answer:

  • 385 mph
  • 350 mph

Step-by-step explanation:

You want the individual speeds of airplanes that close the 2940 mile distance between them in 4 hours, and have a speed difference of 35 mph.

Setup

The closing speed is found using the relation ...

  speed = distance/time

It is ...

  (2940 mi)/(4 h) = 735 mi/h

If x represents the speed of the slower plane, then (x+35) is the speed of the faster one. The sum of their speeds is the closing speed:

  x +(x +35) = 735

Solution

Simplifying, we have ...

  2x +35 = 735

  2x = 700 . . . . . . subtract 35

  x = 350 . . . . . . . divide by 2

  x+35 = 385 . . . . speed of the faster plane

The speeds of the planes are 350 mph and 385 mph.

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