Answered

At a fish fry fundraiser, the math club raised $277.50. child plates were sold for $2.25 and adult plates were sold for $4.75. if there were twice as many child plates sold than adult plates, how many adult plates were sold?

Answer :

The number of adult plates sold are 30.

It is given in the question that:-

Total money raised by math club = $277.50

Cost of a child plate = $2.25

Cost of an adult plate = $4.75

There are twice as many child plates sold than adult plates.

Let the number of adult plates be x.

Hence, according to the question,

Number of child plates = 2x

Using this data, we can form a linear equation,

2.25*2x + 4.75*x = 277.50

4.50x + 4.75x = 277.50

9.25x = 277.50

x = 277.50/9.25

x = 30

Hence, the number of adult plates sold are 30.

To learn more about linear equation, here:-

https://brainly.com/question/11897796

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