Answer :
[tex]{ \qquad\qquad\huge\underline{{\sf Answer}}} [/tex]
Here we go ~
[tex]\qquad \sf \dashrightarrow \: \cfrac{9 {}^{(x + 1)} - 3 {}^{2x} }{4 \times 3 {}^{(2x - 1)} } [/tex]
[tex]\qquad \sf \dashrightarrow \: \cfrac{3{}^{2(x + 1)} - 3 {}^{2x} }{4 \times 3 {}^{(2x - 1)} } [/tex]
[tex]\qquad \sf \dashrightarrow \: \cfrac{3{}^{(2x + 2)} - 3 {}^{2x} }{4 \times 3 {}^{(2x - 1)} } [/tex]
here :
- [tex]{ \sf {3}^{(2x+2)}=({3}^{2x - 1})\sdot (3³)} [/tex]
- [tex]{ \sf {3}^{(2x)}=({3}^{(2x - 1)})\sdot (3¹)} [/tex]
[tex]\qquad \sf \dashrightarrow \: \cfrac{3{}^{(2x - 1)}(3 {}^{3} - 3 {}^{1}) }{4 \times 3 {}^{(2x - 1)} } [/tex]
[ taking [tex]{ \sf {3}^{(2x - 1)} } [/tex]common here ]
[tex]\qquad \sf \dashrightarrow \: \cfrac{27 {}^{} - 3 {}^{}}{4 } [/tex]
[tex]\qquad \sf \dashrightarrow \: \cfrac{24{}^{} {}^{}}{4 } [/tex]
[tex]\qquad \sf \dashrightarrow \: 6[/tex]