Answered

1. Use the following information to answer 3 questions. When heated in a closed container in the presence of a catalyst, potassium chlorate decomposes into potassium chloride and oxygen gas via the following reaction:
2KClO3(s) → 2KCl(s)+ 3O2(g)
If 12.25g potassium chlorate decomposes, how many grams of oxygen will be release?
(A) 1.60 g (B) 3.20 g
(C) 4.80 g (D) 18.37 g

Answer :

4.80 grams of oxygen will be release.

When heated in a closed container in the presence of a catalyst, potassium chlorate decomposes into potassium chloride and oxygen gas via the following reaction:

2KClO3(s) → 2KCl(s)+ 3O2(g)

mass of potassium chlorate   = 12.25g

mole of KClO3 = 12.25/122.5 = 0.1 mol

2 mole KClO3 (consumed) = 3 mole O2 (produced)

1 mole KClO3 = 3/2 mole O2

0.1 mole KClO3 = 0.1*1.5 mole O2

                          = 0.15 mole O2

mass of O2 = 0.15 * 32 = 4.80 grams

4.80 grams of oxygen will be release.

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