KINGCALAMARIGO
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A bullet is fired through a board 10.0 cm thick in such a way that the bullet’s line of motion is perpendicular to the face of the board. If the initial speed of the bullet is 400 m/s and it emerges from the other side of the board with a speed of 300 m/s, find the acceleration of the bullet as it passes through the board and find the total time the bullet is in contact with the board.

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Answer :

LANUELGO
  1. The acceleration of this bullet is equal to 1.25 × 10⁶ m/s².
  2. The total time the bullet is in contact with the board is 8.0 × 10⁻⁵ secs.

Given the following data:

Initial velocity = 400 m/s

Final velocity = 300 m/s

Distance = 10.0 cm to m = 10/100 = 0.1 m.

How to calculate the acceleration of an object?

Mathematically, the acceleration of this bullet can be calculated by using this formula:

a = (V - U)/t

Where:  

  • V represents the final velocity.
  • U represents the initial velocity.
  • t represents the time measured in seconds.
  • a represents the acceleration.

However, we would have to use the third equation of motion to calculate the acceleration of this bullet because we do not know the time taken yet.

Mathematically, the third equation of motion is given by:

V² = -U² + 2aS

300² = -400² + 2(a)(0.1)

0.2a = 160000 + 90000

0.2a = 250000

a = 250000/0.2

Acceleration, a = 350,000

Acceleration, a = 1.25 × 10⁶ m/s².

For the time, we have:

t = (V - U)/a

t = (400 - 300)/1.25 × 10⁶

Time, t = 8.0 × 10⁻⁵ secs.

Read more on acceleration here: brainly.com/question/24728358

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