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A solution of naf is added dropwise to a solution that is 0.0122 m in ba2 . when the concentration of f- exceeds ________ m, will precipitate. neglect volume changes. for , ksp = 1.7 x 10-6. 4. calculate the ph of a solution prepared by dissolving 0.270 mol of weak acid ha (ka = 1.77 x 10-4) and 0.260 mol of its conjugate base in water sufficient to yield 1.00 l of solution.

Answer :

A solution of NaF is added to a solution that is 0.0144 M in Ba²⁺. When the concentration of F- exceeds 0.011 m, BaF₂ will precipitate.

Let's consider the solution of BaF₂.

BaF₂(s) ⇄ Ba²⁺(aq) + 2 F⁻(aq)

We can use the solubility product constant (Ksp) to find the equilibrium concentration of F⁻ when [Ba²⁺] is 0.0144 M.

When [F⁻] exceeds 0.011 M, BaF₂ will precipitate.

A solution of NaF is added to a solution that is 0.0144 M in Ba²⁺. When the concentration of F- exceeds 0.011 M, BaF₂ will precipitate.

What is BaF₂.?

  • BaF2 crystallizes in the cubic Fm3m space group and has a fluorite structural makeup.
  • Eight comparable F1 atoms and Ba2+ are joined in a cubic shape with the body in the middle. The average Ba-F bond length is 2.72.
  • Four comparable Ba2+ atoms are joined with F1 to create a mixture of corner- and edge-sharing FBa4 tetrahedra.

Learn more about BaF2 crystallizes

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