Rachel recorded the number of calls she made at work during the week:

Day Calls
Monday 18
Tuesday 14
Wednesday 24
Thursday 16

She expected to make 18 calls each day. To answer whether the number of calls follows a uniform distribution, a chi-square test for goodness of fit should be performed. (alpha = 0.10)

chi squared equals begin inline style sum from blank to blank of end style fraction numerator left parenthesis O minus E right parenthesis squared over denominator E end fraction

What is the chi-squared test statistic?

The chi-squared test statistic will be 3.11. The test statistic is contrasted with a predicted value based on the Chi-square distribution.

What is the chi-squared test statistic?

Finding the squared difference between the actual and anticipated data values, then dividing that difference by the expected data values, constitutes the test statistic.

The formula for the chi-squared test statistic is;

[tex]\sum \frac{(O_i-E_i)^2}{E_i } \\\\[/tex]

Where,

[tex]\rm O_i[/tex] is the observed value

[tex]\rm E_i[/tex] is the expected value

The chi-square test statics is;

[tex]\rm( \frac{18-18}{18} )^2 +( \frac{14-18}{18} )^2 + (\frac{24-18}{18} )^2+( \frac{16-18}{18} )^2 \\\\ 0+ \frac{16}{18}+ \frac{36}{18} +\frac{4}{18}\\\\ \frac{56}{18} \\\\ 3.11[/tex]

Hence, the chi-squared test statistic will be 3.11.

To learn more about the chi-squared test statistic refer;

https://brainly.com/question/14082240

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