The specific heat of the metal is 0.30J/g°C.
What is specific heat capacity?
The specific heat capacity is defined as the quantity of heat (J) absorbed per unit mass (kg) of the material when its temperature increases 1 K (or 1 °C), and its units are J/(kg K) or J/(kg °C).
Step 1: Data given
Mass of metal = 75.0 g
Temperature of the metal = 65°C
Mass of water = 100.0 g
Temperature of the water = 20.0°C
Final temperature of the water = 22.3 °C
The specific heat of water is 4.184 J/g°C
Step 2: Calculate the specific heat of metal
Qlost = -Qgained
Q= m xCxΔT
Qmetal = -Qwater
m(metal) x c(metal) x ΔT(metal) = - m(water) x c(water) x ΔT(water
⇒m(metal) = the mass of metal = 75.0 g
⇒c(metal) = the specific heat of the metal = ?
⇒ΔT = The change of temperature = 22.3 - 65°C = -42.7 °C
⇒m(water) = the mass of water = 100.0 g grams
⇒c(water) = the specific heat of water = 4.186 J/g°C
⇒ΔT(water) = T2 - T1 = 22.3 - 20.0 = 2.3 °C
75.0 g x c(metal) x -42.7 °C= -100.0 g x 4.186 x 2.3
75.0 g x c(metal) x -42.7 °C = −962.78
c(metal) = 0.3006338798J/g°C =0.30J/g°C
The specific heat of the metal is 0.30J/g°C.
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