Answer:
[tex]f^{-1}(x)=\left(\dfrac{x-7}{3}\right)^2[/tex]
Step-by-step explanation:
Given function:
[tex]f(x)=3\sqrt{x}+7[/tex]
To find the inverse of the function
Swap f(x) for y:
[tex]\implies y=3 \sqrt{x}+7[/tex]
Subtract 7 from both sides:
[tex]\implies y-7=3 \sqrt{x}+7-7[/tex]
[tex]\implies y-7=3\sqrt{x}[/tex]
Divide both sides by 3:
[tex]\implies \dfrac{3\sqrt{x}}{3}=\dfrac{y-7}{3}[/tex]
[tex]\implies \sqrt{x}=\dfrac{y-7}{3}[/tex]
Square both sides:
[tex]\implies \left(\sqrt{x}\right)^2=\left(\dfrac{y-7}{3}\right)^2[/tex]
[tex]\implies x=\left(\dfrac{y-7}{3}\right)^2[/tex]
Swap the x for [tex]f^{-1}(x)[/tex] and y for x:
[tex]\implies f^{-1}(x)=\left(\dfrac{x-7}{3}\right)^2[/tex]
