Let's check
[tex]\\ \rm\dashrightarrow F=\dfrac{k}{q_1q_2}{r^2}[/tex]
[tex]\\ \rm\dashrightarrow F\propto Q[/tex]
[tex]\\ \rm\dashrightarrow F\propto \dfrac{1}{r^2}[/tex]
So
Option A and C can be used
Answer:
Decreasing the distance between the particles by a factor of 2
Explanation:
To double the force between the two charge particles, the distance between the particles should be reduced by a factor of two.
According to coulombs law "force is directly proportional to the potential between the two charges and inversely proportional to the square of their distances".
[tex]\sf{F = \dfrac{kq_{1} q_{2} }{r^{2} }}[/tex]
F is the electric force
k is the coulomb constant
q is the charge
r is the distance or separation
As the separation between the charges is reduced the force increases and vice versa.
