The expression which gives the area of triangle QRS is [tex]\frac{1}{2} (9)(15)sin(20^{o} )[/tex].
We need to find the area of triangle QRS.
How do I find the area of a triangle using trigonometry?
The area of a triangle can be expressed using the lengths of two sides and the sine of the included angle. Area of Δ = ½ ab sin C.
Now, the area of the triangle QRS[tex]=\frac{1}{2} (9)(15)sin(20^{o} )[/tex]
Therefore, the expression which gives the area of triangle QRS is [tex]\frac{1}{2} (9)(15)sin(20^{o} )[/tex].
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