(a)The acceleration of the ball, while it is in flight, will be 9.81 m/s².
(b) The velocity of the ball when it reaches its maximum height will be 0 m/sec.
(c) The initial velocity of the ball is 20.30 m/s upward.
(d) The maximum height it reaches will be 21.00 m
The change of displacement with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.
The given data in the problem is;
u is the initial velocity of fall = ? m/sec
h is the distance of fall = ? m
g is the acceleration of free fall = 9.81 m/sec²
a.
The acceleration of the ball, while it is in flight, is equal to the acceleration due to gravity,g=9.81 m/s².
b.
The ball's velocity will be zero when it has reached its highest point.
c.
The initial velocity of the ball is;
v=u-gt
0=u-gt
u=gt
u=9.81 m/s² × 2.07 sec
u=20.30 m/s
d.
The maximum height it reaches is found by the formula as;
[tex]\rm u^2 = - 2gh \\\\ (20.30)^2 = -2 \times (-9.8) \times h \\\\ 412.09 = 19.6 \times h\\\\ h = 412.09/19.6\\\\ h = 21.00 m[/tex]
Hence the acceleration of the ball,s the velocity of the ball when it reaches its maximum height, the initial velocity of the ball, and the maximum height it reaches will be 9.81 m/s²,0 m/sec,20.30 m/s, and 21.00 m respectively.
To learn more about the velocity, refer to the link: https://brainly.com/question/862972.
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