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The term "freshman 15" refers to the claim that college students typically gain 15lbs during freshman year at college. Assume that the amounts of weight that male college students gain during their freshman year are normally distributed with a mean of 2.9 lb and a standard deviation of 10.4 lb. Find the probability that a randomly selected male college student gains 15 lb or more during their freshman year. What does the result suggest about the claim of the "freshman 15"?

Answer :

The probability that a randomly selected male college student gains 15 lb or more during their freshman year is 11.6%

What is Probability ?

Probability is defined as the likeliness of an event to happen.

Let X be a random variable that shows the term "freshman 15" that claims that students typically gain 15lb during their freshman year at college.

It is given that

X follows is a normal distribution with a mean of 2.1 lb (μ) and a standard deviation (σ)  of 10.8 lb.

Population Mean (μ) = 2.1

Population Standard Deviation (σ) = 10.8

We need to compute Pr(X≥15). The corresponding z-value needed to be computed is:

[tex]\rm Z_{lower} = \dfrac{ X_1 -\mu }{\sigma}\\\\Z_{lower} = \dfrac{ 15-2.1 }{10.8}\\\\\\Z_{lower} = 1.19[/tex]

Then the probability is given as

[tex]\rm Pr(X \geq 16 ) = Pr (\dfrac{X -21}{10.8} \geq \dfrac{15-21}{10.8})\\\\= Pr (Z \geq \dfrac{15-2.1}{10.8}\\\\= Pr (Z\geq 1.19)\\\\ = 0.1162[/tex]

Pr(X≥15)=0.1162. (11.6%)

The probability that a randomly selected male college student gains 15 lb or more during their freshman year is 11.6%

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