Answer :
The total number of digits used when the first 2002 positive even integers are written is 4 digits
How to find the number of sequence?
Using arithmetic sequence,
nth term = a + (n - 1)d
where
- a = first term
- d = common difference
- n = number of terms
a = 2
d = 2
nth term = 2 + (2002 - 1)2
nth term = 2 + 4002
nth term = 4004
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