Answer:
(5, 18) and (-5, 38)
Step-by-step explanation:
Given system of equations:
1) f(x) = x² - 2x + 3 ⇒ y = x² - 2x + 3
2) f(x) = -2x + 28 ⇒ y = -2x + 28
Solve using the Substitution Method:
Step 1: Substitute the the first equation into the second equation.
⇒ x² - 2x + 3 = -2x + 28
Step 2: Solve for x.
x² - 2x + 3 = -2x + 28 [ Add 2x to both sides. ]
x² - 2x + 2x + 3 = -2x + 2x + 28
⇒ x² + 3 = 28 [ Subtract 28 from both sides. ]
x² + 3 - 28 = 28 - 28
⇒ x² - 25 = 0 [ Factor using the following rule: a² - b² = (a - b)(a + b). ]
(x - 5)(x + 5) = 0
⇒ x - 5 = 0, x + 5 = 0 [ Solve for the values of x. ]
x - 5 + 5 = 0 + 5, x + 5 - 5 = 0 - 5
⇒ x = 5, x = -5
Step 3: Solve for y.
Substitute the found x-values into one of the given equations.
y = x² - 2x + 3 ⇒ y = (5)² - 2(5) + 3 ⇒ y = 25 - 10 + 3 ⇒ y = 18
y = x² - 2x + 3 ⇒ y = (-5)² - 2(-5) + 3 ⇒ y = 25 + 10 + 3 ⇒ y = 38
The solutions to the system of equations are:
⟹ x₁ = 5, y₁ = 18 ⇒ (5, 18)
⟹ x₂ = -5, y₂ = 38 ⇒ (-5, 38)
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