Answer:
n = -5
Step-by-step explanation:
Given:
[tex]\dfrac{y^4 \cdot y^n}{y^2}=y^{-3}[/tex]
Multiply both sides by y²:
[tex]\implies \dfrac{y^4 \cdot y^n}{\diagup \!\!\!\!\!y^2} \cdot \diagup \!\!\!\!\!y^2=y^{-3}\cdot y^2[/tex]
[tex]\implies y^4 \cdot y^n=y^{-3} \cdot y^2[/tex]
[tex]\textsf{Apply exponent rule} \quad a^b \cdot a^c=a^{b+c}:[/tex]
[tex]\implies y^{4+n}=y^{-3+2}[/tex]
[tex]\implies y^{4+n}=y^{-1}[/tex]
[tex]\textsf{Apply exponent rule} \quad a^{f(x)}=a^{g(x)} \implies f(x)=g(x):[/tex]
[tex]\implies 4+n=-1[/tex]
Solve for n by subtracting 4 from both sides:
[tex]\implies 4+n-4=-1-4[/tex]
[tex]\implies n=-5[/tex]
Answer:
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Given equation:
Solve it for n:
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Used properties:
