The owner of a small deli is trying to decide whether to discontinue selling magazines. He suspects that only 9.7% of his customers buy a magazine and he thinks that he might be able to use the display space to sell something more profitable. Before making a final decision, he decides that for one day he will keep track of the number of customers that buy a magazine. Assuming his suspicion that 9.7% of his customers buy a magazine is correct, what is the probability that exactly 5 out of the first 10 customers buy a magazine?

We have to find the probability that exactly 5 out of the first 10 customers buy a magazine. Probability is the chance of happening an event among all the events possible.

The binomial distribution is the probability of exactly x successes on n repeated trials and X can only have two outcomes.

[tex]P(X=x)=C_{n,x}p^{x} (1-p)^{n-x}[/tex]

In which [tex]C_{n,x}=n!/x!(n-x)![/tex]

And P is the probability of happening of X.

In the question 9.7% of his customers buy a magazine.

So the value of P=0.097

This can be calculated by :

P(X=5) when n=13

[tex]P(X=x)=C_{n,x} p^{x} (1-p)^{n-x}[/tex]

[tex]P(X=5)=C_{10,5} (0.097)^{5} (1-0.097)^{10-5}[/tex]

=[tex]P(X=5)=C_{10,5} (0.097)^{5} (0.903)^{5}[/tex]

[tex]=10!/5!5!*0.0000085*0.600397[/tex]

=252*0.00000510

=0.001286

Hence the probability that exactly 5 out of the first 10 customers buy a magazine is 0.001286.

Learn more about probability at https://brainly.com/question/24756209

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