The equation that best models the data is (a) y = 186 - 6.2x
The data is not provided; so I would give a general guide on how to model a linear equation.
Assume the points on the line are:
(0,186) and (1,179.8)
Start by calculating the slope of the line using:
[tex]m = \frac{y_2 - y_1}{x_2 -x_1}[/tex]
This gives
[tex]m = \frac{179.8 - 186}{1 - 0}[/tex]
Evaluate
m = -6.2
The equation is then calculated using:
[tex]y = m(x - x_1) + y_1[/tex]
This gives
y = -6.2(x - 0) + 186
Evaluate
y = -6.2x + 186
Rewrite as:
y = 186 - 6.2x
Hence, the equation that best models the data is (a) y = 186 - 6.2x
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