Using the hypergeometric distribution, it is found that there is a 0.1363 = 13.63% theoretical probability of 5 students from your school being selected as contestants out of 10 possible contestant spots.
The formula is:
[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}[/tex]
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
The parameters are:
The values of the parameters are given as follows:
N = 130, k = 40, n = 10.
The theoretical probability of 5 students from your school being selected is P(X = 5), hence:
[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}[/tex]
[tex]P(X = 5) = h(5,120,10,40) = \frac{C_{40,5}C_{80,5}}{C_{120,10}} = 0.1363[/tex]
0.1363 = 13.63% theoretical probability of 5 students from your school being selected as contestants out of 10 possible contestant spots.
More can be learned about the hypergeometric distribution at https://brainly.com/question/24826394
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