The mean and standard deviation for the number of boys in the 950 babies are 475 and 15.41, respectively
From the complete question, we have:
P(boy)= 0.5
Sample size = 950
The mean is then calculated as:
[tex]\bar x = np[/tex]
This gives
[tex]\bar x = 950 * 0.5[/tex]
Evaluate
[tex]\bar x = 475[/tex]
The standard deviation is calculated as:
[tex]\sigma = \sqrt{np(1 - p)[/tex]
This gives
[tex]\sigma = \sqrt{950 * 0.5(1 - 0.5)[/tex]
Evaluate
[tex]\sigma = 15.41[/tex]
Hence, the mean and standard deviation for the number of boys in the 950 babies are 475 and 15.41, respectively
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