what does it want me to put to 6 decimal places

They want you to solve the iterative process to a point where the value of x is greater than or equal to 6 decimal places.
An iterative process is a mathematical approach that employs an initial value to build a series of improving estimated solutions for a problem, where the nth-term estimation is generated from the prior ones.
You're required to put the value of x₁ = -1 into the equation:
[tex]\mathbf{x_{n+1}= \dfrac{(x_n)^3-1}{4}}[/tex]
So;
[tex]\mathbf{x_{2}= \dfrac{(-1)^3-1}{4}}[/tex]
[tex]\mathbf{x_{2}=-0.5}[/tex]
[tex]\mathbf{x_{3}= \dfrac{(-0.5)^3-1}{4}}[/tex]
[tex]\mathbf{x_{3}=-0.28125}[/tex]
[tex]\mathbf{x_{4}=\dfrac{(-0.28125)^3-1}{4}}[/tex]
[tex]\mathbf{x_{4}=-0.2555618286}[/tex]
x₄ ≅ -0.255562 ( to 6 decimal places)
Learn more about the iterative process here:
https://brainly.com/question/26995556
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