find the distance and displacement for the following figures :

The figure (i) have a distance of 15.996 meters and a displacement of 13.892 meters and (ii) a distance of 480 centimeters and a displacement of 339.411 centimeters
The distance is the sum of the lengths that form a trajectory and the displacement is the distance between the initial and final point of a trajectory. Then, we have the following results for each case:
Case I
Distance
d = 5 m + 0.5π · (7 m)
d ≈ 15.996 m
Displacement
[tex]D = \sqrt{(12\,m)^{2}+(7 m)^{2}}[/tex]
D ≈ 13.892 m
Case II
Distance
d = 8 · (60 cm)
d = 480 cm
Displacement
[tex]D =\sqrt{(240\,cm)^{2}+(240\,cm)^{2}}[/tex]
D ≈ 339.411 cm
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